$4x^2y-6x^2y^2+10xy$
$5+\frac{2x}{x-3}=\frac{6}{x-3}$
$6x^2-19x-7$
$\frac{120}{-24}$
$-3x^29x^4-8-4x^1+\frac{1}{2}x$
$\frac{2}{7}y-\frac{3}{7}y$
$\left(m-3\right)\left(m+5\right)$
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