$x^3y'+2y^2=0$
$-18\left(12+13\right)$
$\frac{3}{5}x-\frac{1}{5}x-\frac{2}{5}x+\frac{1}{5}x$
$3y'-6y=9e^2x$
$\left(4x^2+5y^2\right)\left(4x^2-5y^2\right)$
$18^9$
$\lim_{x\to0}\left(\frac{t-sen\left(t\right)}{t^{\frac{5}{3}}}\right)$
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