$\frac{x-6}{3}\le x+4$
$\left(\frac{-2x}{x+1}\right)>2$
$\left(8+3a^3\right)\left(64-24a^3+9a^6\right)$
$\frac{sen^2x}{\cos x}.secx$
$\int12e^{4x}dx$
$\int\frac{\ln\left(y\right)}{3y^3}dy$
$\left(a+1\right)^4$
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