$\left(x+\frac{5}{6}\right)^2=\frac{169}{36}$
$\sqrt{a^9}\sqrt[3]{\left(b+1\right)}^5-81\sqrt{a}\sqrt[3]{\left(b+1\right)}$
$-6x\left(-3x-10\right)$
$\frac{dy}{dx}\left(2x-3y=1\right)$
$\frac{dy}{dx}=2\cos5x$
$\frac { y ^ { 10 } } { y ^ { - 5 } }$
$\frac{\sec\left(x\right)-1}{\tan\left(x\right)}=\frac{\tan\left(x\right)}{\sec\left(x\right)-1}$
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