$\int\frac{3}{4}x^{\frac{8}{5}}dx$
$\frac{dx}{dt}\:+\:xt\:=\:0,\:x\left(0\right)\:=\:5$
$\int\frac{x}{\sqrt[3]{x-8}}dx$
$x^{-3}y^2$
$3x^2+16x+5$
$-41x^3-63x^2-28x-4$
$\frac{-6x-5}{3}<\frac{4x-4}{2}$
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