$\frac{x^2}{64}-\frac{y^2}{36}=1$
$\frac{\left(sin\left(2y\right)\right)}{1+cos\left(2y\right)}$
$\left(b+1\right)\left(b-3\right)$
$\left(-5+a\right)\left(-5-a\right)$
$4x^2-12xy+16y^2$
$-106-43$
$5\cdot37$
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