$x^8dydx+7x^2=0$
$\left(m^{10}\right)^4$
$\sqrt{9\cdot16}$
$\frac{7}{x-4}-\frac{5}{x+7}$
$-y^2+2y+16$
$\frac{dy}{dx}=x^9-5x^8+x+12$
$tanxsec^2x\frac{1}{3}+\frac{2}{3}tanx$
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