$25x^2-10x\:+\:1$
$\frac{d}{dx}2x^2+y^5=8$
$\frac{10x}{10x^2}$
$\lim_{x\to+\infty}\left(\frac{x}{\sqrt{x+1}}\right)$
$\frac{dy}{dx}=\left(\frac{y-3}{x-5}\right)$
$\left(\left(2^{-2}\right)^3\right)^{-3}$
$\frac{3x}{1+3x}<1$
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