$-20+2\cdot5-3$
$y^8-256$
$y'=t^2+1,\:y\left(1\right)=4$
$2a^2\left(-5\:a^{-6}\right)\left(-2a\right)$
$\frac{dy}{dx}=e\left(1+y\right)$
$f\left(x\right)=\frac{x\tan\left(x\right)}{8x^7+34}$
$8^{4x-3}=32^{2x+1}$
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