$\tan\left(89\right)-\tan\left(44\right)-\tan\left(89\right)\cdot\tan\left(44\right)$
$\left(x^2\right)^{6-3}$
$-1250+-3600$
$4x+2x+1$
$\frac{\sec\left(x\right)^2}{\tan\left(x\right)^2}=\frac{1}{\sin\left(x\right)^2}$
$\left(-13p^3q^4\right).\left(-8p^7q^5r\right)\:$
$4x^3-2x^2y$
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