$\log_bx^4\sqrt[3]{y}$
$\frac{dy}{dx}=y^3\sin\left(2x\right)$
$\int\left(\frac{-x^4+x^3+2}{x^4}\right)\:dx$
$\frac{d}{dx}x^3+x^2y+2y^4=8$
$-y^2+6y^2$
$6^6\:+6^{-2}$
$sec\:b\:+\:tan\:b\:=\:\frac{cos\:b}{1\:-\:sin\:b}$
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