$\frac{x}{6}+7=12$
$\frac{3-x^4+x^2-2}{x^2+1}$
$36x^3y^2+42x^2y^3-6x^2y^2$
$16x^2-64x-32^2$
$\left(42\right).\left(-23\right)$
$\lim_{x\to\infty}\left(2x^4-x^3\right)$
$\arcsin\left(1.94843\right)$
Get a preview of step-by-step solutions.
Earn solution credits, which you can redeem for complete step-by-step solutions.
Save your favorite problems.
Become premium to access unlimited solutions, download solutions, discounts and more!