$\lim_{x\to-\infty}\left(\frac{\sqrt{4x^2+1}}{2x-3}\right)$
$\sqrt{64a^4}$
$rs+4s$
$3x^2-2x+1\:.\:x-2$
$7+8\left(4+5\right)$
$y'=4e^x+y$
$3\left(y+4\right)+7\left(y-3\right)+5$
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