$\lim_{x\to5\:}\left(\frac{x^3-11x^2+18x+40}{x-5}\right)$

$\frac{549}{-9}$

$\frac{dy}{dx}yx+y^2+5xy^2=0$

$2x^5-8x^2+4$

$4x-3<2x-5$

$-2\cdot\left(-5+\left(5-1\right)\right)\cdot\left(-3\right)+2-\left(2-5\right)\cdot\left(-2-1\right)$

$\lim_{x\to0}\left(\frac{e^{x^2}-cos\left(x\right)}{x^2+x}\right)$