$\frac{x\:+\:4}{x^2\:+\:x\:-\:12}$
$x^2-\left(y-2\right)^2$
$\:3x\:-\:b\:\:x\:=\:6\:.\:$
$\frac{3-2w+5w^3}{w-1}$
$10y+3x-7-6y-2x$
$6x^{6-1}$
$14\left(10b+11\right)$
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