$\int\frac{1}{\left(x^4+4\right)}dx$
$2+\left(-6\right)^{2}$
$\int\frac{x-4}{x^2+7x+6}dx$
$x10+5y^212$
$x\:+\:10=-15$
$\lim_{x\to\infty}\left(x^2ln\left(1+\frac{1}{x}\right)\right)$
$\frac{12}{x}+x-8=0$
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