$\left(\frac{2c^3d}{4cd^4}\right)^{-3}$
$\lim_{x\to\infty}\left(\frac{ln\left(5\right)}{1+ln\left(x\right)}\right)$
$3a^2b^2c^2.4ab^3.5c^6$
$x+2y=y$
$( x ^ { 2 } + 5 ) ^ { 4 }$
$\left(x^216y+x^613y\right)$
$\frac{x^3+3x^2-x-3}{x+3}\:$
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