$\lim_{x\to0}\left(\sqrt{x^2+4ax}-\sqrt{x^2+4bx}\right)$
$-8+13+\left(-24\right)+6\left(-4\right)$
$-14-3x<-1$
$15\le x+2$
$\left(\frac{2x^2}{4x^4}\right)^3$
$2ab+4a-9a-18$
$\left(\frac{8a^5b^{-2}c}{10a^{-3}b^4}\right)^3\left(\frac{15a^{10}}{4y^{-3}}\right)^{-3}$
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