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The trinomial $x^2-18x+81$ is a perfect square trinomial, because it's discriminant is equal to zero
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$\Delta=b^2-4ac=-18^2-4\left(1\right)\left(81\right) = 0$
Learn how to solve polynomial factorization problems step by step online. Factor the expression x^2-18x+81. The trinomial x^2-18x+81 is a perfect square trinomial, because it's discriminant is equal to zero. Using the perfect square trinomial formula. Factoring the perfect square trinomial.