$2.3\cdot10^8+4.7\cdot10^7$

$9x^2-12x-4x^2-8x-x^2$

$\frac{\sin2x+\sin6x}{\cos2x+\cos6x}=\tan\left(4x\right)$

$\frac{\tan\left(x\right)}{\cos\left(x\right)}+\frac{1}{1+\sin\left(x\right)}=\frac{4}{3}$

$\left|-16-\left(-5\right)\right|+\left(-2\right)\cdot6-8$

$\left(-2\right)+\left(-54\right)-\left(-14\right)$

$45t^5-14t^5$