$\left(3x^4+4y^2\right)^3$
$2x^2+4x-6=0$
$x+13=20$
$\frac{\sqrt{x^3-1}+\sqrt{x-1}}{\sqrt{x^2-1}}$
$3x^3-2x-1$
$2x^2+12x=-9$
$9m+12\cdot9m-12$
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