$3\cdot1\cdot\left(-13\right)$
$\int12jkg^{-1}dg$
$3-2\left(x+4\right)>2-2x$
$12-\left(-6\right)$
$9x^2-12x+3$
$\int-2\:\cos\left(x\right)\sin^6\left(x\right)dx$
$420=z+25$
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