$\left(w-6\right)\left(w+5\right)$
$\lim_{x\to\infty}\left(\frac{e^{x^2}}{6-x^3}\right)$
$-\left[-\left(7+8\right)+\left(4-3\right)\right]-2$
$8a^5+\:125a^2$
$\lim_{x\to\infty}\left(\frac{\cos\left(4x\right)-\cos^2\left(2x\right)}{x}\right)$
$2t\cdot4t$
$5x^3+2x^2-4x-3$
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