$\int\frac{3x}{\left(x+3\right)\left(x+4\right)}dx$
$x^2+4x-1=0$
$5+3y^2=2x^3$
$\frac{dy}{dx}-\frac{3y}{x+1}=\left(x+1\right)^4$
$\sin\left(\frac{2}{2.23}\right)$
$\lim_{x\to\infty}\left(_{\frac{\left(x+1\right)}{x+2}}\right)$
$cos\left(2x\right)=\frac{4}{5}$
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