$216-y^6$
$5x^{3y}-15xy^2+25xy$
$6x+15\le33$
$\int\frac{\sqrt{x^2-4}}{y^3}dx$
$-7<\frac{g}{-1}-4$
$a\frac{1}{7}+b\frac{1}{7}$
$\frac{4\left(x-4\right)}{x^2+2x-8}=\frac{4}{x+4}$
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