$2\left(3x-1\right)^2$
$\frac{dy}{dx}=\frac{x}{y+2}$
$y^4-40y^2+124$
$\left(x^4-9\right)\left(x^4+1\right)$
$\cos\left(150\right)^2+2\sin\left(150\right)^2=\:0$
$sec^4\left(x\right)\:-\:tan^4\left(x\right)\:$
$\left(4x+3y+1\right)dx+\left(3x+2y+1\right)dy=0$
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