$\cos\left(x\right)^2=\frac{\cos\left(x\right)}{\sec\left(x\right)}$
$\left(x^2+5x+4x+20\right)$
$\int9e^{-3x}dx$
$\frac{-12w^9z^4}{144w^2z^3}$
$\left(3b-6\right)^2$
$6.5-7$
$\left(10d-h\right)^2$
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