$\frac { x ^ { 4 } - 4 x ^ { 2 } + 6 } { x + 2 }$
$cos6x=1$
$3x+11\le6\left(x+8\right)$
$\left(6+ba\right)\cdot\left(6-a\right)$
$\frac{2x^3-6x^2-5x+15}{x-3}$
$4x^2-4x+7$
$\sqrt{-121}$
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