$8\int dx$
$\left(0.4m^6-1.2m^4\right)^2$
$\left(x^3+4x^3y^4\right)dx+e^{x^4}y^3dy=0$
$m\left(m+\frac{2m+4}{2m}\right)+\:\frac{1}{m^2}$
$x+\sqrt{3x+8}=2x+2$
$\lim_{x\to\infty}\left(\frac{x+1}{x+2}\right)$
$a^2-26a+169$
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