$\int x\:\sin\left(\frac{1}{6}x\right)dx$
$\int\frac{1}{x^2-7x-6}dx$
$19\:-\:\left(-34\right)$
$\lim_{x\to7}\left(\frac{x^2-4x-21}{35-5x}\right)$
$100.35=x^2+100.48$
$\left(3+4\cdot2-6\right)$
$x^2\:-\:kx\:+\:144\:=\:0$
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