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# Find the break even points of the expression $x^2+x=5$

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##  Final answer to the problem

$x=\frac{-1+\sqrt{21}}{2},\:x=\frac{-1-\sqrt{21}}{2}$
Got another answer? Verify it here!

##  Step-by-step Solution 

How should I solve this problem?

• Find break even points
• Solve for x
• Find the derivative using the definition
• Solve by quadratic formula (general formula)
• Simplify
• Find the integral
• Find the derivative
• Factor
• Factor by completing the square
• Find the roots
Can't find a method? Tell us so we can add it.
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Rewrite the equation

$x^2+x-5=0$

Learn how to solve classify algebraic expressions problems step by step online.

$x^2+x-5=0$

Learn how to solve classify algebraic expressions problems step by step online. Find the break even points of the expression x^2+x=5. Rewrite the equation. To find the roots of a polynomial of the form ax^2+bx+c we use the quadratic formula, where in this case a=1, b=1 and c=-5. Then substitute the values of the coefficients of the equation in the quadratic formula: \displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}. To obtain the two solutions, divide the equation in two equations, one when \pm is positive (+), and another when \pm is negative (-). Multiply -4 times -5.

##  Final answer to the problem

$x=\frac{-1+\sqrt{21}}{2},\:x=\frac{-1-\sqrt{21}}{2}$

##  Explore different ways to solve this problem

Solving a math problem using different methods is important because it enhances understanding, encourages critical thinking, allows for multiple solutions, and develops problem-solving strategies. Read more

SnapXam A2

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4
5
6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

###  Main Topic: Classify algebraic expressions

An algebraic expression can be classified as a monomial, binomial, trinomial or polynomial, depending on the number of terms.