$2-4r=6$

$-2a<56$

$\int\frac{x^2+11x+15}{x^3+3x^2-4}dx$

$\sin\left(x\right)^2\left(\tan\left(x\right)\right)+\left(\cos\left(x\right)\right)\left(\sin\left(x\right)\right)=\left(\tan\left(x\right)\right)$

$\int8x^2\:sin9x^3\:dx$

$\lim_{x\to0}\left(\frac{x}{1+x^2}\right)$

$y=\frac{\left(x\sqrt{x^3+3}\right)}{\left(x+1\right)^2}$