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Find the break even points of the expression $x^2+x+3=5$

Step-by-step Solution

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Final Answer

$x=1$
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Step-by-step Solution

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Grouping all terms to the left side of the equation

$x^2+x+3-5=0$

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$x^2+x+3-5=0$

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Learn how to solve classify algebraic expressions problems step by step online. Find the break even points of the expression x^2+x+3=5. Grouping all terms to the left side of the equation. Subtract the values 3 and -5. Sort the polynomial -2+x^2+x in descending order to handle it more easily. Factor the trinomial x^2+x-2 finding two numbers that multiply to form -2 and added form 1.

Final Answer

$x=1$

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1
2
3
4
5
6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

How to improve your answer:

Main Topic: Classify algebraic expressions

An algebraic expression can be classified as a monomial, binomial, trinomial or polynomial, depending on the number of terms.

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