$4005\cdot7$

$\frac{d}{dx}+\frac{1}{3}y=\frac{4}{3}$

$\int\left(6x^2-3x+2\left(12x-3\right)\right)dx$

$\left(5a\right)+\left(7b\right)^2$

$\frac{\cot\left(x\right)^2}{\csc\left(x\right)}+\frac{\tan\left(x\right)^2}{\sec\left(x\right)}$

$35:-5$

$13+12\left(-11\right)$