$\frac{1+3\cos\left(y\right)}{1+\cos\left(y\right)}=\frac{1+2\cos\left(y\right)-3\cos\left(y\right)^2}{\sin\left(y\right)^2}$

$\sqrt[3]{a^4b^3c^8}$

$\left(-12-m\right)^2$

$\left(x\:+\:12y\right)\:\left(x\:-\:6y\right)$

$-x^2-7-30$

$\sqrt{2y}.\sqrt{6}.\sqrt{8x}$

$\int_1^4\left(\frac{4}{x}\left(\frac{81}{2x^2}-\frac{x^2}{2}\right)\right)dx$