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Find the roots of $x^2+6x=-911$

Step-by-step Solution

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Final Answer

$x=\frac{-6+60.06663i}{2},\:x=\frac{-6-60.06663i}{2}$
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Step-by-step Solution

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$x^2+6x+911=0$

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$x^2+6x+911=0$

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Learn how to solve trigonometric integrals problems step by step online. Find the roots of x^2+6x=-911. Rewrite the equation. To find the roots of a polynomial of the form ax^2+bx+c we use the quadratic formula, where in this case a=1, b=6 and c=911. Then substitute the values of the coefficients of the equation in the quadratic formula: \displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}. Simplifying. To obtain the two solutions, divide the equation in two equations, one when \pm is positive (+), and another when \pm is negative (-).

Final Answer

$x=\frac{-6+60.06663i}{2},\:x=\frac{-6-60.06663i}{2}$

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1
2
3
4
5
6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

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Main Topic: Trigonometric Integrals

Integrals that contain trigonometric functions and their powers.

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