$\frac{1}{4}-\frac{1}{4}\cos\left(2x\right)=\frac{1}{8}\sin\left(x\right)^2$
$4n^2-17n+4$
$y^2+xy+y'=0$
$\left(x+10\right)\left(y+5\right)$
$\frac{u^{-2}-6u^{-1}}{-u^{-2}}$
$-1xyz^2+3\left(xy^2-xy^2z\right)$
$\left(8+5\right)-\left(3+7\right)$
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