$\left(16-x^2\right)\left(x^2-16\right)$
$3x+6>2x+15$
$\int\frac{1}{\sin^2u+1}du$
$\frac{30x^{-4}}{6x^6}$
$\left[\left(12x+11\right)\cdot\:\left(8x+9\right)\right]+\left[112x+56x\:2\:+56\:\right]$
$\left(3x^2+4z^4\right)^2$
$\frac{dy}{dx}\left(b^2x^2+a^2y^2=a^2b^2\right)$
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