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Find the break even points of the expression $x^2+5x-25=5$

Step-by-step Solution

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Final Answer

$x=3.520797$
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Step-by-step Solution

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Group the terms of the equation by moving the terms that have the variable $x$ to the left side, and those that do not have it to the right side

$x^2+5x=5+25$

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$x^2+5x=5+25$

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Learn how to solve classify algebraic expressions problems step by step online. Find the break even points of the expression x^2+5x+-25=5. Group the terms of the equation by moving the terms that have the variable x to the left side, and those that do not have it to the right side. Add the values 5 and 25. Rewrite the equation. To find the roots of a polynomial of the form ax^2+bx+c we use the quadratic formula, where in this case a=1, b=5 and c=-30. Then substitute the values of the coefficients of the equation in the quadratic formula: \displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}.

Final Answer

$x=3.520797$

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Plotting: $x^2+5x-25-5$

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5
6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

How to improve your answer:

Main Topic: Classify algebraic expressions

An algebraic expression can be classified as a monomial, binomial, trinomial or polynomial, depending on the number of terms.

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