$\sqrt{x}\left(4-x^2\right)$
$\lim_{x\to\infty}\sqrt{x}\cdot e^{\frac{x}{2}}$
$4a\:-\:6b+2a\:+6b$
$-5+8-3+2-10-12-17-16+5+4$
$\lim_{x\to\infty}\left(\frac{180x}{x^2+9}\right)$
$6x^2+5x-56$
$3^5\cdot3^4$
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