$\left(2x-3y^2\right)^4$
$\left(3x\right)^3-2^3$
$225t^4-1$
$-3x+4x$
$3-\:\left(-1\:\right)\:-\:11$
$\frac{\left(x\right)}{-6}\le-20$
$-\frac{7}{8}a+a$
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