$x^2\cdot4y\cdot2x^4$

$-2\left(-1\right)^5-3\left(-1\right)^3+2\left(-1\right)+1$

$3\int\sqrt{2x+7}dx$

$\left(2\cos\left(a\right)\right)^2+\left(3\sin\left(a\right)\right)^2=3-\left(\cos\left(a\right)\right)^2$

$17x-10x+7$

$\left(0\right)^3-2\left(0\right)^2+0-9$

$\frac { 4 } { x } = 2$