$-2\cdot0+3$
$\lim_{x\to0}\left(\frac{\cos\left(x\right)}{3x+1}\right)$
$\frac{m^3+8}{m+2}$
$16x^{-3}=x$
$21-\left(-29\right)$
$5\left(9y-4\right)$
$x^4-2x^3+2x^2+\frac{-5}{x+2}$
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