$\sqrt[3]{-48a^6b^9}$
$\frac{10^4}{10}$
$f^2+10f+16$
$+8-3+\left(17-42\right)-\left(51-7-8\right)$
$\int\frac{1}{\left(x^2+7x+6\right)}dx$
$\left(a+b\right)\left(b-a\right)\left(a^2+b^2\right)+b^4$
$\left(1+\frac{1}{\sin\left(x\right)}\right)\cdot\left(\sin\left(x\right)-\sin^2\left(x\right)\right)$
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