$a^{2}+20a+10$
$\lim_{x\to-3}\left(1.66x^2\right)\left(x-9\right)$
$8\left(6t-2v+5\right)$
$\left(-5\right)-\left(-40\right)$
$\sqrt[4]{32x^4y^{10}}$
$\frac{a^3+8a^2+15x+6}{a^2+7a+6}$
$\:\left(10x\:+\:3\right)\:\left(10x\:-\:1\right)$
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