$\frac{3}{5}m^2+40m+\frac{1}{10}m^2+m^2$
$\left(3x^3+4y^2+z\right)^2$
$-8d-10c+17c+d-4c$
$4x\cdot\frac{3}{2}x^3$
$8csc\:a=0$
$\left(6z^2-5w^3\right)^2$
$\int_{-1}^2\left(x^2-4x+3\right)-\left(-x^2+2x+3\right)dx$
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