$x^4+3x^3-9x^2+5x$
$\frac{dy}{dx}=x\sqrt{y}cosx$
$9r^2+42r+49$
$\frac{4x^3-x^2+5x-10}{x+5}$
$\frac{5^{-1}}{-9^0}$
$\left(3z\:5\:+7z\:2\:\right)\:$
$\left(n^2+7\right)\left(n^2-3\right)$
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