$t=\left(t-0\right)$
$\int\left(\frac{1}{6}\right)\left(\frac{x+8}{x^2+2x-6}\right)dx$
$+2-1-6+3-9$
$f\left(x\right)=2x^2+5x^2-2$
$\sqrt[3]{2\left(10^2+2^3\right)}$
$\int6x^4\sqrt[4]{x^5+8}dx$
$\frac{0}{\sqrt{a+b}}$
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