$2a^3+6a^2-4a$
$\frac{5}{3\sqrt{v+4}}$
$5x^2-9x+6=8x^2-15x+9$
$3\int sec\left(\theta\right)d\left(\theta\right)$
$2y\left(3y^2+4y^4\right)$
$4\left(x-5\right)+3x-10$
$5x^2-4x=0$
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