$\int\frac{2^{arc\arctan\left(x\right)}}{1+x^2}dx$

$x-8=\left(-a-b\right)x+\left(2a+3b\right)$

$\frac{-2^3+-2-5}{3\left(-2\right)+5}$

$\int\:\frac{1}{\left(x-1\right)\cdot\left(x^2-2x+2\right)^2}dx$

$3x-4y=8$

$3\:x\:\left(4^2\right)$

$\lim_{x\to\infty}\left(xln\frac{x+3}{x+1}\right)$